wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

(1+x)2x+x3dx is equal to

A
logex+loge(1+x2)+k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
logex+tan1x+k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
logex+2tan1x+k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C logex+2tan1x+k
(1+x)2x+x3dx
=x2+2x+1x(1+x2)dx
x2+2x+1x(1+x2)=1x+2(1+x2)
x2+2x+1x(1+x2)dx=logex+2tan1x+k

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Parametric Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon