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Question

[log(logx)]mxlogxdx=

A
[log(log(x))]m+1m+1+c
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B
[log(log(x))]mm+c
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C
[log(log(x))]m+1m+c
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D
[log(log(x))]mm+1+c
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Solution

The correct option is A [log(log(x))]m+1m+1+c
I=[log(logx)]mxlogxdx

Put log(logx)=t
1xlogxdx=dt

I=tmdt
=tm+1m+1
I=[log(log(x))]m+1m+1+c

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