Question

${\int }_{-\frac{\pi }{2}}^{\frac{\pi }{2}}\sin xdx$ is equal to

• A. $0$
• B. $1$
• C. $-1$
• D. $2$

Answer 1

The correct option is A $0$

${\int }_{-\pi /2}^{\pi /2}\sin xdx\sin (-x)=-\sin x\therefore \sin x\text{is an odd function}\therefore {\int }_{\pi /2}^{\pi /2}\sin x.dx=0$