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Question

x(x2+4)x2+1dx=1ktan1x2+13+c. what is k?

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Solution

I=x(x2+4)x2+1dx
Let x2+I=t2orxdx=tdt
I=tdt(t2+3)t
=13tan1t3+c
=13tan1x2+13+c
k=3

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