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Byju's Answer
Standard IX
Mathematics
Coordinates of Points and Distances
L1 is a line ...
Question
L
1
is a line intersecting
x
and
y
axis at
P
(
a
,
0
)
and
Q
(
0
,
b
)
.
L
2
is a line perpendicular to
L
1
intersecting
x
and
y
axis at
R
and
S
respectively
If the area of the triangle
O
R
S
is 4 times the area of the triangle
O
P
Q
then equation of
P
S
is
A
x
+
2
y
=
2
b
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B
2
x
+
y
=
2
a
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C
x
−
2
y
+
2
b
=
0
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D
2
x
−
y
−
2
a
=
0
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Solution
The correct options are
B
2
x
+
y
=
2
a
D
2
x
−
y
−
2
a
=
0
Area of the
△
O
R
S
=
1
2
a
b
k
2
=
4
×
1
2
a
b
⇒
k
2
=
4
⇒
k
=
±
2
Equation of
P
S
is
x
a
±
y
2
a
=
1
⇒
2
x
±
y
=
2
a
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0
Similar questions
Q.
L
1
is a line intersecting
x
and
y
axes at
A
(
a
,
0
)
and
B
(
0
,
b
)
.
L
2
is a line perpendicular to
L
1
intersecting
x
and
y
axes at
C
and
D
respectiveley. If the area of the triangle
O
C
D
is 4 times the area of triangle
O
A
B
, then equation of
A
D
is
Q.
L
1
is a line intersecting
x
and
y
axes at
A
(
a
,
0
)
and
B
(
0
,
b
)
.
L
2
is a line perpendicular to
L
1
intersecting
x
and
y
axes at
C
and
D
respectiveley. If the area of the triangle
O
C
D
is 4 times the area of triangle
O
A
B
, then equation of
A
D
is
Q.
A straight line
L
1
:
x
a
+
y
b
=
1
intersects the
x
-axis and
y
-axis at
P
and
Q
respectively and a straight line
L
2
perpendicular to
L
1
cuts the
x
-axis and
y
-axis at
R
and
S
respectively. The locus of the point of intersection of the lines
P
S
and
Q
R
is
Q.
A line
L
1
:
2
x
−
2
y
+
5
=
0
is rotated about its point of intersection with
y
−
axis such that
L
1
becomes
L
2
and area of the triangle formed by
L
1
,
L
2
and
x
=
4
is
13
sq. unit
, then
L
2
will be
Q.
If
L
1
is the line of intersection of the planes
2
x
−
2
y
+
3
z
−
2
=
0
,
x
−
y
+
z
+
1
=
0
and
L
2
is the line of intersection of the planes
x
+
2
y
−
z
−
3
=
0
,
3
x
−
y
+
2
z
−
1
=
0
, then the distance of the origin from the plane, containing the lines
L
1
and
L
2
is :
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