Question

$\underset{n\to \infty }{lim}\frac{(2n-1)(3n+5)}{(n-1)(3n+1)}=$

• A. $2$
• B. $\infty$
• C. $0$
• D. $Noneofthese$

Answer 1

The correct option is A $2$

${lim}_{x\to \infty }\frac{(2n-1)(3n+5)}{(n-1)(3n+1)}$

$={lim}_{x\to \infty }\frac{(2-(1/n\left)\right)(3+(5/n\left)\right)}{(1-(1/n\left)\right)(3+(1/n\left)\right)}$

${lim}_{x\to \infty }\frac{\left(2\right)\left(3\right)}{\left(1\right)\left(3\right)}=2$