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Question

limn[11+n2+222+n2+...+nn2+n2] is

A
log2
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B
2log2
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C
log22
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D
log23
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Solution

The correct option is B log22

limnnr=1rn2+r2
=limnnr=11n(rn)1+(rn)2

=10x1+x2dx
=1210d(x2)1+x2

=12log(1+x2)|10

=12log(2)


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