limx→0+=4x(2x−1)−1(2x−1)x2limx→0+=4x(2x−1)−1(2x−1)x2limx→0+=limh→0(40+h−1)(20+h−1)x2limx→0+=limh→0(40+h−1)(20+h−1)x2ThenweuseD.Lhospitalrule:limx→0+=4xlog4(2x−1)+(4x−1)2xlog22xItisalso00formlimx→0+=(23x−4x)log4+(23x−2x)log22xlimx→0+=(23x−4x)log4+(23x−2x)log22x=(log8−log4)log4+(log8−log2)log2223x=(23)x=8x23x=(23)x=8x=2log2⋅log42=log2⋅log4