The correct option is A 11 lim_x→∞8|x|+3x/3|x| 2x= Since, x is positive so #160; | x |=x lim_x→∞8x+3x/3x 2x lim_x→∞ #160;11x ...

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Derivative from First Principle

limx→∞8|x|+3x...

Question

$lim x \to \infty \frac{8 | x | + 3 x}{3 | x | - 2 x} =$

11

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8

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0

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\frac{1}{8}

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Solution

The correct option is A $11$
$lim x \to \infty \frac{8 | x | + 3 x}{3 | x | - 2 x} =$
Since, $x$ is positive so $| x | = x$
$lim x \to \infty \frac{8 x + 3 x}{3 x - 2 x}$
$lim x \to \infty \frac{11 x}{x} = 11$

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