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Sulphuric Acid

Na 2 S 2 O 3 ...

Question

${N a}_{2} S_{2} O_{3}$ reacts with ${C l}_{2}$ to form ${N a}_{2} {S O}_{4}, H C l$ and $X - -$ . Which one of the following is $X - -$ ?

H_{2} S

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{S O}_{2}

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{S O}_{3}

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S

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Solution

The correct option is C $S$
$N a_{2} S_{2} O_{3} + C l_{2} + H_{2} O \to N a_{2} S O_{4} + S + 2 H C l$ .

Thus compound X is $S$ .

$N a_{2} S_{2} O_{3}$ reacts with chlorine in the presence of water to form sodium sulphate, $H C l$ and $S$ .

Hence, option $D$ is correct.

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