The correct option is B 2^16 17 Consider given the binomial expression, #10; #10; #10; #10; #10;∑_r=2^16^16C_r=^16C_2+^16C_3+^16C_3+.......^16 ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Sum of Coefficients of All Terms

∑r=21616Cr=

Question

$16 \sum r = 2^{16} C_{r} =$

2^{15} - 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2^{16} - 16

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2^{16} - 17

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2^{17} - 17

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $2^{16} - 17$
Consider given the binomial expression,

${16 \sum r = 2^{16} C_{r} =}^{16} C_{2} +^{16} C_{3} +^{16} C_{3} + {. . . . . . .}^{16} C_{16}$

$= 2^{16} - 17$

Hence, this is the answer.

Suggest Corrections

Similar questions

18

35

15

37

30

415

17

68

216

215

81

16

1) \frac{18}{23} \times (\frac{4}{9} \times \frac{6}{7}) = (\frac{18}{23} \times \frac{4}{9}) \times \frac{6}{7}

2) \frac{16}{17} \times (\frac{3}{4} + \frac{20}{31}) = (\frac{16}{17} \times \frac{3}{4}) + (\frac{16}{17} \times \frac{20}{31})

216

215

\frac{343 \times 49}{216 \times 16 \times 81} = ?

2 \sqrt[4]{81} - 8 \sqrt[3]{216} + 15 \sqrt[5]{32} + \sqrt{225} - \sqrt[4]{16}

Join BYJU'S Learning Program