X - 1limx2-x-lnx-lnx-1-x-1

x → 1limx^2 x.lnx+lnx 1/x 1 =x → 1lim2x 1 lnx+1/x/1 (Using L hospital's rule) =2 ...

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Existence of Limit

x → 1limx2-x....

Question

$l i m x \to 1 \frac{x^{2} - x . l n x + l n x - 1}{x - 1}$

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Solution

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