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Integration by Parts

x 2 -2<0 whic...

Question

$x^{2} - 2 < 0$ which of the following specifies all the possible values of x ?

0 < x < 2

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- 2 < x < 0

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\sqrt{- 2}

x

\sqrt{2}

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- 2 < x < 2

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Solution

The correct option is C $\sqrt{- 2}$ < $x$ < $\sqrt{2}$
$\Rightarrow (x - \sqrt{2}) (x + \sqrt{2}) < 0$

$∴ x ϵ (- \sqrt{2}, \sqrt{2})$

$\Rightarrow - \sqrt{2} < x < \sqrt{2}$

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