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Question

Dissociation of sodium azide is given by,
NaN3Na+3/2N2
ΔH for this is__________.

A
3/2ΔHof(N2)ΔHof(NaN3)
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B
ΔHof(NaN3)
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C
ΔHof(NaN3)[ΔHof(Na)+3/2ΔHof(N2)]
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D
[ΔHof(Na)+3/2ΔHof(N2)]ΔHof(NaN3)
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Solution

The correct option is C ΔHof(NaN3)
NaN3Na+3/2N2
ΔH=ΔH0f(products)ΔH0f(reactants)
=ΔH0f(Na)+32ΔH0f(N2)ΔH0f(NaN3)
But Na and N2 are in their standard states.
ΔH0f(Na)=ΔH0f(N2)=0
ΔH=ΔH0f(NaN3)

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