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Contact Process

dissolves in ...

Question

_________ dissolves in water to produce sulphuric acid.

A

S O_{2}

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B

S

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C

S O_{3}

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D

2 S

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Solution

The correct option is B $S O_{3}$
$S O_{3}$ dissolves in water to produce sulphuric acid.
$S O_{3} + H_{2} O \to H_{2} S O_{4}$
$S O_{2}$ dissolves in water to produce sulphurous acid.
$S O_{2} + H_{2} O \to H_{2} S O_{3}$

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Similar questions

In the contact process, $S O_{3}$ is dissolved in concentrated Sulphuric acid to produce:

S + O_{2} ⟶ S O_{2}

Δ H = - 398.2 k J

S O_{2} + \frac{1}{2} O_{2} ⟶ S O_{3}

Δ H = - 98.7 k J

S O_{3} + H_{2} O ⟶ H_{2} S O_{4}

Δ H = - 130.2 k J

H_{2} + \frac{1}{2} O_{2} ⟶ H_{2} O

Δ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at

298 K

In the contact process, $S O_{3}$ is dissolved in concentrated Sulphuric acid to produce:

Q. What is the catalyst used for oxidation of

S O_{2}

S O_{3}

in lead chamber process for manufacture of sulphuric acid?

S + O_{2} \to S O_{2}; Δ H = - 398.2 k J; S O_{2} + \frac{1}{2} O_{2} \to S O_{3}; Δ H = - 98.7 k J

S O_{2} + H_{2} O \to H_{2} S O_{4}; Δ H = - 130.2 k J; H_{2} + \frac{1}{2} O_{2} \to H_{2} O; Δ H = - 227.3 k J

The enthalpy of formation of sulphuric acid at

298

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