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Question

If S+O2SO2; ΔH=398.2 kJ: SO2+12O2SO3; ΔH=98.7 kJ
SO3+H2OH2SO4; ΔH=130.2 kJ : H2+12O2H2O; ΔH=227.3 kJ
The enthalpy of formation of sulphuric acid at 298 K will be?

A
854.4 kJ
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B
754.4 kJ
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C
650.3 kJ
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D
433.7 kJ
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Solution

The correct option is B 854.4 kJ
Solution:- (A) 854.4kJ
Given:-
S+O2SO2ΔH=398.2kJ.....(1)
SO2+12O2SO3ΔH=98.7kJ.....(2)
SO3+H2OH2SO4ΔH=130.2kJ.....(3)
H2+12O2H2OΔH=227.3kJ.....(4)
Adding eqn(1),(2),(3)&(4), we have
H2+S+2O2H2SO4ΔH=854.4kJ
Hence the enthalpy of formation of sulphuric acid is 854.4kJ.

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