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Question

# If S+O2⟶SO2; ΔH=−398.2 kJ: SO2+12O2⟶SO3; ΔH=−98.7 kJSO3+H2O⟶H2SO4; ΔH=−130.2 kJ : H2+12O2⟶H2O; ΔH=−227.3 kJThe enthalpy of formation of sulphuric acid at 298 K will be?

A
854.4 kJ
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B
754.4 kJ
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C
650.3 kJ
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D
433.7 kJ
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Solution

## The correct option is B −854.4 kJSolution:- (A) −854.4kJGiven:-S+O2⟶SO2ΔH=−398.2kJ.....(1)SO2+12O2⟶SO3ΔH=−98.7kJ.....(2)SO3+H2O⟶H2SO4ΔH=−130.2kJ.....(3)H2+12O2⟶H2OΔH=−227.3kJ.....(4)Adding eqn(1),(2),(3)&(4), we haveH2+S+2O2⟶H2SO4ΔH=−854.4kJHence the enthalpy of formation of sulphuric acid is −854.4kJ.

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