Distance of the point (1, 2, 3) from the co-ordinate axes are
13, 10, 5
√13,√10,√5
√5,√13,√10
1√13,1√10,1√5
From x-axis =√y2+z2=√4+9=√13 From y-axis = √1+9=√10 From z-axis = √1+4=√5.
If the sum of the squares of the distance of a point from the three co-ordinate axes be 36,then its distance from origin