Distance traveled by a particle at any instant ' $t$ ' can be represented as $S = A (t + B) + C t^{2}$ . The dimensions of $B$ are

[M^{0} L^{1} T^{- 1}]

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[M^{0} L^{0} T^{1}]

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[M^{0} L^{- 1} T^{- 2}]

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[M^{0} L^{2} T^{- 2}]

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Solution

The correct option is A $[M^{0} L^{0} T^{1}]$
In $S = A (t + B) + C t^{2}$ ; B is added to time t.
Therefore, dimensions of B are those of time $= [M^{0} L^{0} T^{1}]$ .

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Distance traveled by a particle at any instant 't' can be represented as S=A(t+B)+Ct2. The dimensions of B are

The correct option is A [M0L0T1]In S=A(t+B)+Ct2; B is added to time t. Therefore, dimensions of B are those of time =[M0L0T1].

Distance traveled by a particle at any instant ' $t$ ' can be represented as $S = A (t + B) + C t^{2}$ . The dimensions of $B$ are

The correct option is A $[M^{0} L^{0} T^{1}]$
In $S = A (t + B) + C t^{2}$ ; B is added to time t.
Therefore, dimensions of B are those of time $= [M^{0} L^{0} T^{1}]$ .