Question

Distance travelled by a particle at any instant $t$ can be represented as $S=A(t+B)+C{t}^2$. The dimensions of $B$ are

• A. $\left[M^0{L}^0{T}^{-1}\right]$
• B. $\left[M^0{L}^0{T}^1\right]$
• C. $\left[M^0{L}^1{T}^1\right]$
• D. $\left[M^0{L}^{-2}{T}^1\right]$

Answer 1

The correct option is B $\left[M^0{L}^0{T}^1\right]$

Given relation is $S=A(t+B)+C{t}^2$
Since, $B$ is added to time $t$, so, it will have dimensions of time i.e. $\left[M^0{L}^0{T}^1\right]$