Question

Divide 20 into 2 parts such that the product of 2 numbers is 36.

• A. $18,2$
• B. $9,4$
• C. $10,10$
• D. None

Answer 1

The correct option is A $18,2$

Let one number = $x$
Then other number = $20-x$
$\left(x\right)(20-x)=36$
$20x-x^2=36$
$x^2-20x+36=0$
$(x-2)(x-18)=0$
$x=2,x=18$