Question

Divide:
$4\sqrt{2}{y}^3$ by $3\sqrt{2}{y}^2$

• A. $\dfrac{4}{3}y$
• B. $\displaystyle \frac{1}{3}y$
• C. $\displaystyle \frac{7}{3} y$
• D. $\displaystyle \frac{13}{3}y$

Answer 1

The correct option is A $\dfrac{4}{3}y4 \sqrt2 y^3\div 3 \sqrt2 y^2=\displaystyle \frac { 4\sqrt { 2 } y^{ 3 } }{ 3\sqrt { 2 } y^{ 2 } } =\frac { 2\times 2\times \sqrt { 2 } \times y\times y\times y }{ 3\times \sqrt { 2 } \times y\times y } =\displaystyle \frac {4y} {3}$