wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Divide and Simplify:
4a2+12ab+9b225c2 by 2a+3b+5c.

Open in App
Solution

4a2+12ab+9b225c2
=(2a)2+2×2a×3b+(3b)2(5c)2
=(2a+3b)2(5c)2
=(2a+3b+5c)(2a+3b5c)
4a2+12ab+9b225c2÷(2a+3b+5c)
=(2a+3b+5c)(2a+3b5c)(2a+3b+5c)=2a+3b5c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Method of Common Factors 2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon