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Algebraic Identities

Factorise: 4a...

Question

Factorise:
$4 a^{2} - 9 b^{2} - 2 a - 3 b$

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Solution

$4 a^{2} - 9 b^{2} - 2 a - 3 b = (2 a)^{2} - (3 b)^{2} - 2 a - 3 b = (2 a - 3 b) (2 a + 3 b) - 1 (2 a + 3 b) = (2 a + 3 b) [(2 a - 3 b) - 1] = (2 a + 3 b) [2 a - 3 b - 1]$

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Similar questions

Q. Factorise the following :
i)

3 - 12 (a - b)^{2}

4 a^{2} - 9 b^{2} - 2 a - 3 b

4 a^{2} - 9 b^{2} - 2 a - 3 b

4 a^{2} + 12 a b + 9 b^{2} - 25 c^{2}

2 a + 3 b + 5 c

Q. Divide and Simplify:

4 a^{2} + 12 a b + 9 b^{2} - 25 c^{2}

2 a + 3 b + 5 c

4 a^{2} + 9 b^{2} + 16 c^{2} + 12 a b - 24 b c - 16 a c

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