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Question

Divide and Simplify:
4a2+12ab+9b225c2 by 2a+3b+5c.

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Solution

4a2+12ab+9b225c2
=(2a)2+2×2a×3b+(3b)2(5c)2
=(2a+3b)2(5c)2
=(2a+3b+5c)(2a+3b5c)
4a2+12ab+9b225c2÷(2a+3b+5c)
=(2a+3b+5c)(2a+3b5c)(2a+3b+5c)=2a+3b5c

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