Divide and verify the following
$14 x^{2} + 13 x - 15$ by $(7 x - 4)$

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Solution

$\begin{matrix} Q u o t i e n t = 2 x + 3 r e m a i n d e r = 7 d i v i d e n d = 14 x^{2} + 13 x - 5 d i v i s o r = 7 x - 4 \Rightarrow d i v i s o r \times q u a t i e n t + r e m a i n d e r \Rightarrow (7 x - 4) \times (2 x + 3) + 7 \Rightarrow 14 x^{2} + 21 x - 8 x - 12 + 7 \Rightarrow 14 x^{2} + 13 x - 5 = d i v e d e n d h e b c e, v a r i f i e d . \end{matrix}$

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