Question

Divide by using long division method.

$96$ by $3$

Answer 1

Let us divide $96$ by $3$

Step 1 : Divide $9$ tens by $3$ i.e., $9÷3=3$

Write $3$ in the tens place of the quotient and write product $9$, below the dividend in the tens place. $9-9=0$

Step 2 : Bring down $6$

$6÷3=2$

Write $2$ in the ones place of the quotient and write $6$ below the dividend in ones place. $6-6=0$

$$\begin{gathered} 32 \\ 3⟌96 \\ -9\downarrow \\ 06 \\ -6 \\ 0 \end{gathered}$$

Hence, the required quotient is $32$ and remainder is $0$.