Divide: $(- 16 x^{6} - 24 x^{4})$ by $(- {8 x}^{3})$

{2 x}^{3} + 3 x

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{2 x}^{2} + 3

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- {2 x}^{3} - 3 x

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- {2 x}^{2} - 3

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Solution

The correct option is C ${2 x}^{3} + 3 x$
$(- 16 x^{6} - 24 x^{4}) \div (- {8 x}^{3}) = \frac{- 16 x^{6} - 24 x^{4}}{- {8 x}^{3}}$

$= \frac{- 8 x^{4} ({2 x}^{2} + 3)}{{8 x}^{3}}$

$= x ({2 x}^{2} + 3)$

$= {2 x}^{3} + 3 x$

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