Question

Divide:
(i) $12x^3{y}^2$ by $3x^{2}y$
(ii) $-15a^{2}b{c}^3$ by $3ab$

Answer 1

(i) We have,
$\frac{12x^3{y}^2}{3x^{2}y}=\frac{12\times x\times x\times x\times y\times y}{3\times x\times x\times y}=4\times x\times y=4xy$
(ii) We have,
$\frac{-15a^{2}b{c}^3}{3ab}=\frac{-15\times a\times a\times b\times c\times c\times c}{3\times a\times b}=-5a{c}^3$