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Question

Divide :
(i)12x3y2 by 3x2y (ii)15a2bc3 by 3ab

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Solution

(i) We have,
12x3y23x2y=12×x×x×x×y×y3×x×x×y=4×x×y=4xy

(ii) We have,
15a2bc33ab=15×a×a×b×c×c×c3×a×b=5ac3

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