Divide:
i) $24 x^{2} y^{3}$ by $3 x y$
ii) $- 27 x^{2} y^{2} z$ by $- 12 x y z$

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Solution

(i) $\frac{24 x^{2} y^{3}}{3 x y}$ = $8 x y^{2}$
(ii) $\frac{- 27 x^{2} y^{2} z}{- 12 x y z}$ = $\frac{9 x y}{4}$

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