Divide:
(i) $24 x^{2} y^{3}$ by $3 x y$
(ii) $36 x y z^{2}$ by $- 9 x z$
(iii) $- 72 x^{2} y^{2} z$ by $- 12 x y z$
(iv) $- 56 m n p^{2}$ by $7 n m p$

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Solution

(i) $24 x^{2} y^{3} \div 3 x y$
$= \frac{24 x^{2} y^{3}}{3 x y} = 8 x^{2 - 1} y^{3 - 1} = 8 x y^{2}$

(ii) $36 x y z^{2} \div - 9 x z$
$= \frac{36 x y z^{2}}{- 9 x z} = - 4 y z^{2 - 1} = - 4 y z$

(iii) $- 72 x^{2} y^{2} z b y - 12 x y z$
$= \frac{- 72 x^{2} y^{2} z}{- 12 x y z} = 6 x^{2 - 1} y^{2 - 1} = 6 x y$

(iv) $- 56 m n p^{2} b y 7 n m p$
$= \frac{- 56 m n p^{2}}{7 m n p} = - 8 p^{2 - 1} = - 8 p$

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