Question

Divide the following.
(i) $6\sqrt[3]{325}$ by $2\sqrt{5}$ (ii) $25\sqrt[4]{433}$ by $5\sqrt[4]{411}$ (iii) $5\sqrt[3]{34}$ by $3\sqrt{2}$

Answer 1

(i) $\frac{6\sqrt[3]{325}}{2\sqrt{5}}=\frac{6}{2}\frac{\sqrt[6]{6(25{)}^2}}{\sqrt[6]{65^3}}=\frac{6}{2}.\sqrt[6]{6\frac{625}{125}}=3\sqrt[6]{65}$
(ii) $\frac{25\sqrt[4]{433}}{5\sqrt[4]{411}}=\frac{25}{5}\sqrt[4]{4\frac{33}{11}}=5\sqrt[4]{43}$
(iii) $\frac{5\sqrt[3]{34}}{3\sqrt{2}}=\frac{5}{3}\sqrt[6]{6\frac{16}{8}}=\frac{5}{3}\sqrt[6]{62}$