Divide the given polynomial by the given monomial:
$(x^{3} + 2 x^{2} + 3 x) \div 2 x$

1/2(x²+2x+3)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1/2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(x²+2x+3)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1/2(x²+2x+3)

Divide all the terms of the expression $(x^{3} + 2 x^{2} + 3 x)$ separately by $2 x$ .
$\Rightarrow x^{3} \div 2 x = \frac{x^{2}}{2}$
$\Rightarrow \frac{2 x^{2}}{2 x} = x$
$\Rightarrow \frac{3 x}{2 x} = \frac{3}{2}$
Therefore, $\frac{(x^{3} + 2 x^{2} + 3 x)}{2 x} = \frac{(x^{2} + 2 x + 3)}{2}$

Suggest Corrections

Similar questions

Divide the given polynomial by the given monomial:
$(x^{3} + 2 x^{2} + 3 x) \div 2 x$

Q. Question 2(iv)
Divide the given polynomial by the given monomial

(x^{3} + 2 x^{2} + 3 x) \div 2 x

Divide the given polynomial by the given monomial.

$(i) (5 x^{2} - 6 x) \div 3 x$

$(i i) (3 y^{8} - 4 y^{6} + 5 y^{4}) \div y^{4}$

$(i i i) 8 (x^{3} y^{2} z^{2} + x^{2} y^{3} z^{2} + x^{2} y^{2} z^{3}) \div 4 x^{2} y^{2} z^{2}$

$(i v) (x^{3} + 2 x^{2} + 3 x) \div 2 x$ . [4 MARKS]

Q. Question 2(iv)
Divide the given polynomial by the given monomial

(x^{3} + 2 x^{2} + 3 x) \div 2 x

Divide the given polynomial by the given monomial:
$(2 y^{3} + 3 y^{2} + 12 y) \div 3 y$

Join BYJU'S Learning Program

Divide the given polynomial by the given monomial: (x3+2x2+3x)÷2x

The correct option is A 1/2(x2+2x+3) Divide all the terms of the expression (x3+2x2+3x) separately by 2x. ⇒x3÷2x=x22 ⇒2x22x=x ⇒3x2x=32 Therefore, (x3+2x2+3x)2x=(x2+2x+3)2

Divide the given polynomial by the given monomial:
$(x^{3} + 2 x^{2} + 3 x) \div 2 x$