Question

Divide the sum $\frac{2}{3}$ and $\left(\frac{-5}{6}\right)$ by the product of $\frac{-3}{4}$ and $\frac{-1}{3}$.

Answer 1

Divide the sum $\frac{2}{3}$ and $\frac{-5}{6}$ by products $\frac{-3}{4}$ and $\frac{-1}{3}$

$=\frac{\frac{2}{3}+\frac{-5}{6}}{\frac{-3}{4}\times \frac{-1}{3}}$

$=\frac{\frac{4-5}{6}}{\frac{3}{12}}$

$=\frac{\frac{-1}{6}}{\frac{3}{12}}$

$=\frac{-1}{6}\times \frac{12}{3}$

$=-\frac{2}{3}$