Divide $x (3 x^{2} - 27)$ by $3 (x - 3)$

x + 3

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x²+ 3x

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x+3x²

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x²+ 3

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Solution

The correct option is B
x²+ 3x

$x (3 x^{2} - 27) = 3 x (x^{2} - 9) = 3 x (x + 3) (x - 3)$

$\frac{3 x (x + 3) (x - 3)}{3 (x - 3)} = x (x + 3) = x (x + 3) = x^{2} + 3 x$ .

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Dividing $x (3 x^{2} - 27)$ by $3 (x - 3)$ gives $x^{2} + 3 x$ .

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