Divide(y2+10y+24)÷(y+4)
We have (y2+10y+24)(y+4)
=(y2+4y+6y+24)(y+4) [On factorisation, 10y=4y+6y]
=[y(y+4)+6(y+4)](y+4)
=[(y+4)(y+6)](y+4)
=(y+6)