Dividing $(a + b)^{2} + (a - b)^{2}$ by $(a^{2} + b^{2})$ gives___.

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Solution

$(a + b)^{2} + (a - b)^{2}$

$= (a^{2} + b^{2} + 2 a b) + (a^{2} + b^{2} - 2 a b)$

$= 2 (a^{2} + b^{2})$

Thus, $\frac{((a + b)^{2} + (a - b)^{2})}{(a^{2} + b^{2})} = 2$

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Dividing $(a + b)^{2} + (a - b)^{2}$ by $(a^{2} + b^{2})$ gives ___

Dividing $(a + b)^{2} + (a - b)^{2}$ by $a^{2} + b^{2}$ gives:

Q. Simplify

\frac{a + \sqrt{a^{2} - b^{2}}}{a - \sqrt{a^{2} - b^{2}}} + \frac{a - \sqrt{a^{2} - b^{2}}}{a + \sqrt{a^{2} - b^{2}}}

\frac{\sqrt{a^{2} - b^{2}} + a}{\sqrt{a^{2} + b^{2}} + b} \div \frac{\sqrt{a^{2} + b^{2}} - b}{a - \sqrt{a^{2} - b^{2}}}

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

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Dividing (a+b)2+(a−b)2 by (a2+b2) gives___.

(a+b)2+(a−b)2 =(a2+b2+2ab)+(a2+b2−2ab) =2(a2+b2) Thus, ((a+b)2+(a−b)2)(a2+b2)=2

Dividing $(a + b)^{2} + (a - b)^{2}$ by $(a^{2} + b^{2})$ gives___.

$(a + b)^{2} + (a - b)^{2}$

$= (a^{2} + b^{2} + 2 a b) + (a^{2} + b^{2} - 2 a b)$

$= 2 (a^{2} + b^{2})$

Thus, $\frac{((a + b)^{2} + (a - b)^{2})}{(a^{2} + b^{2})} = 2$