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Question

Do the following subtractions as directed.
Subtract the sum of (a2−3a) and 7 from the sum of 3a2 and 2a−2

A
4a2+5a+9
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B
2a2+5a9
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C
2a2+5a+9
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D
4a25a+9
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Solution

The correct option is A 2a2+5a9
The sum of a23a and 7 is a23a+7 and the sum of 3a2 and 2a2 is 3a2+2a2.

We know that Like terms are terms that contain the same variables raised to the same power.

We group together the like terms and subtract a23a+7 from 3a2+2a2 as follows:

(3a2+2a2)(a23a+7)=3a2+2a2a2+3a7=(3a2a2)+(2a+3a)+(27)=2a2+5a9

Hence, (3a2+2a2)(a23a+7)=2a2+5a9.

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