does acetone and benzene together show a positive deviation they increase vapour pressure and decrease the boiling point?

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Question 25
On the basis of information given below mark the correct option. Information On adding acetone to methanol some of the hydrogen bonds between methanol molecules break.
(a) At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show positive deviation from Raoult's law
(b) At specific composition methanol-acetone mixture will form maximum boiling azeotrope and will show positive deviation from Raoult's law
(c) At specific composition methanol-acetone mixture will form minimum boiling azeotrope and will show negative deviation from Raoult's law
(d) At specific composition methanol-acetone mixture will form maximum boiling azeotrope and will show negative deviation from Raoult's law

Q. Acetone and carbon disulphide form binary liquid solution showing positive deviation from Raoult's law. The normal boiling point

(T_{b})

of pure acetone is less than that of pure

C S_{2}

. Pick out the incorrect statements among the following.

Q. Which of the following will show a negative deviation from raoults law?
A. Acetone-benzene
B. Acetone-ethanol
C. Benzene- methanol
D. Acetone-chloroform

For a solution to form positive deviation,the solute-solvent interactions must be less than solute-solute and solvent-solvent interactions,making it easier for the molecules to escape in its pure form.still,why does the vapour pressure of the solution showing positive deviation increase compared to the pure form?

Q. How many pair(s) among the following show positive deviation from ideal behaviour?

___

(A) Acetone and Benzene
(B) HCl and Water
(C) Ethyl alcohol and Water
(D)

C C l_{4}

and

C H C l_{3}

(E) Ethyl chloride and Ethyl bromide
(F) Water and

H C l O_{4}

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