Question

Does ${\mathrm{CO}}_2$ has delocalized pi bonds?

Answer 1

The $\mathrm{\pi }$ bond localization of ${\mathrm{CO}}_2$ is explained below:

1. A delocalized $\mathrm{\pi }$ bond is a bond in which between two nuclei electrons are free to move.
2. However in ${\mathrm{CO}}_2$ molecule the electrons of $\mathrm{\pi }$ bond are fixed in constrained position in the absence of any attacking reagent.
3. Hence, there are no delocalized $\mathrm{\pi }$ bonds present in carbon dioxide$\left({\mathrm{CO}}_2\right)$.
4. Therefore, the above points clearly explains the $\mathrm{\pi }$ bond localization of ${\mathrm{CO}}_2$.