Does the escape speed of a body from the earth depend on (a) the mass of the body, (b) the location from where it is projected, (c) the direction of projection, (d) the height of the location from where the body is launched?

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Solution

The escape velocity of an object is given by,

v esc = 2gR

Where, g is acceleration due to gravity and R is the radius of the earth.

The above equation shows that the escape velocity is independent on the mass of the body and direction of its projection.

It depends on gravitational potential at the point from where the body is launched.

The escape velocity also marginally depends on the height of the point from where it is launched as the potential slightly depends on the height.

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Similar questions

Does the escape speed of a body from the earth depend on

(a) the mass of the body,

(b) the location from where it is projected,

(d) the height of the location from where the body is launched?

11.2 k m s^{- 1}

45

^{\circ}

\frac{3}{4}

11.2 k m s^{- 1}

45^{0}

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