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Question

Domain of f(x)=y=log3cos(sinx) is

A
3{2π2:nZ}
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B
{2nπ:nZ}
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C
{nπ:nZ}
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D
None of thses
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Solution

The correct option is D {nπ:nZ}
Here y would take real values if
log3cos{(sinx)}0cos(sinx)1
But 1cosθ1
cos(sinx)=1
sinx=0
x=nπ,nZ
Hence, the domain consists of the multiples of π i.e., domain
(y)={nπ:nZ}

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