Don-t hate me for asking this question- as it will need you to work your calculator- So- in the radioactive decay 238 Pu -234 U -What will be the kinetic energy of the outgoing -particle- Things you will need- Atomic masses- m 238 Pu -238-04955 u - m 234 U -234-04095 u - m 4 He -4-002603 u- Constant- c 2-931 MeV - u-A- 4-72 MeVB- 5-58 MeVC- 5-03 MeVD- 3-34 MeV

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Byju's Answer

Standard XII

Physics

Alpha Decay

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Question

Don't hate me for asking this question, as it will need you to work your calculator! So, in the radioactive decay -
$^{238} P u \to^{234} U + α,$
What will be the kinetic energy of the outgoing α-particle?
Things you will need:

5.58 MeV

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4.72 MeV

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5.03 MeV

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3.34 MeV

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Solution

The correct option is A 5.58 MeV
This apparent loss in mass of the system of decay products will manifest itself as kinetic energy of the alpha particle. This energy is called the Q value of the decay. Therefore,
$K i n e t i c e n e r g y o f α = Q v a l u e = [m (^{238} P u) - {m (^{234} U) + m (^{4} H e)}] \times c^{2}$
$= [238.04955 u - (234.04095 u + 4.002603 u)] \times 931 \frac{M e V}{u}$
$= \begin{matrix} 5.58 M e V \end{matrix} .$

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Similar questions

So, in the radioactive decay - $^{238} P u \to^{234} U + α,$
What will be the kinetic energy of the outgoing α-particle?
Things you will need:

Don't hate me for asking this question, as it will need you to work your calculator! So, in the radioactive decay -
$^{238} P u \to^{234} U + α,$
What will be the kinetic energy of the outgoing α-particle?
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Q. Radiometric dating is a technique used to find the age of materials on Earth, using the concept of radioactive decay (by measuring the relative abundance of the parent and daughter nuclei). One example of this is Uranium-Thorium dating, used for dating sediments, wherein Uranium-238 goes through a single alpha decay to give Thorium-234:

^{238} U \to^{234} T h + α

What will the Q-value of the process be?
Things you will need:
1. Atomic masses:

m (^{238} U) = 238.0508 u; m (^{234} U) = 234.04363 u; m (^{4} H e) = 4.00260 u

.
2. Constant:

c^{2} = 931 M e V / u

Q. The kinetic energy of the

α

- particle emitted in the decay

_{94}^{238} P u \to_{92}^{234} U +

_{2}^{4} H e

.
(The atomic masses of

^{238} P u,^{234} U

and

α

particle are 238.04955u, 234.04095 u and 4.002603u respectively. Neglect any recoil of the nucleus)

^{238} U \to^{234} T h + α,

What will the Q-value of the process be?
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Don't hate me for asking this question, as it will need you to work your calculator! So, in the radioactive decay - 238Pu→234U+α, What will be the kinetic energy of the outgoing α-particle? Things you will need:

Don't hate me for asking this question, as it will need you to work your calculator! So, in the radioactive decay -
$^{238} P u \to^{234} U + α,$
What will be the kinetic energy of the outgoing α-particle?
Things you will need: