Question

Double bond equivalent of $C_4{H}_6$ is :

• A. 0
• B. 1
• C. 2
• D. 3

Answer 1

Answer: (C)

2

$DBE$ $=$ $Double$ $bond$ $equivalace$

=( number of c ) + 1 - $\frac{\left(numberofh\right)}{2}$

$DBE\left(C_4{H}_6\right)$ $=$ $4+1-$ $\frac{6}{2}$ $=2$