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Question

Draw a histogram to represent the following data:
Class interval10141420203232525280frequency5692521

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Solution

Sol:

Class interval 10-14 14-20 20-32 32-52 52-80
Frequency 5 6 9 25 21

In the above table, class intervals are of unequal size, so we calculate the adjusted frequency by using the following formula:

Adjusted Frequency = Minimumclasssize×itsfrequencyClasssizeofthisclass

Thus, the adjusted frequency table is:

Class Intervals Frequency Adjusted Frequency
10-14 5 45×5=5
14-20 6 46×6=4
20-32 9 412×9=3
32-52 25 420×25=5
52-80 21 428×21=3

Now, take class intervals along x-axis and adjusted frequency along y-axis and constant rectangles having their bases as class-size and height as the corresponding adjusted frequencies.

Thus, we obtain the histogram as shown below:

https://lh6.googleusercontent.com/wTY9lN9Gp7up76Pz-b2Z8tW0vYgTBGzqpxVeXdxPBVZ1kA0uzD7J8wK_kbD2JbxbjLQZc1hHVUQiyNSPEC8F8o5WcxOfWEXxjYyccE-VTuoezxFOj95AtnMcVtWBER4AaOav7kNM


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