Question

Question 7
Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are $\frac{5}{3}$ times the corresponding sides of the given triangle.

Answer 1

Steps of Construction:
Step I:BC = 3 cm is drawn.
Step II:At B, A ray making an angle of ${90}^{\circ }$ with BC is drawn.
Step III:With B as centre and radius equal to 4 cm, an arc is made on the previous ray intersecting it at point A.

Step IV:AC is joined to form $\Delta ABC$.
Step V:A ray BX is drawn making an acute angle with BC opposite to vertex A.
Step VI:5 points $B_1,B_2,B_3,B_{4}and{B}_5$ are marked at equal distances on BX.
Step VII:$B_{3}C$ is joined $B_5{C}^{\prime }$ is made parallel to $B_{3}C$.
Step VIII:A'C' is joined together.
Thus, $\Delta A^{\prime }B{C}^{\prime }$ is the required triangle.