Question

Draw a right triangle in which the sides (other than the hypotenuse) are of lengths 4 cm and 3 cm. Now construct another triangle whose sides are $\frac{3}{5}$ times the corresponding sides of the given triangle.

Answer 1

Construct a right triangle of sides $\mathrm{AB}=4\mathrm{cm},\mathrm{AC}=3\mathrm{cm}\mathrm{and}\angle \mathrm{A}=90°$ and then a triangle similar to it whose sides are ${\left(\frac{3}{5}\right)}^{\mathrm{th}}$of the corresponding sides of.

We follow the following steps to construct the given

Step of construction

Step: I- First of all we draw a line segment AB = 4 cm.

Step: II- With A as centre and draw an angle.

Step: III- With A as centre and radius AC = 3 cm.

Step: IV-Join BC to obtain right .

Step: V- Below AB, makes an acute angle $\angle BAX$.

Step: VI- Along AX, mark off five points $A_1,A_2,A_3,A_4\mathrm{and}{A}_5$ such that $=A_4{A}_5$.

Step: VII- Join $A_{5}B$.

Step: VIII -Since we have to construct a triangle each of whose sides is ${\left(\frac{3}{5}\right)}^{\mathrm{th}}$ of the corresponding sides of right .

So, we draw a line on AX from point which is $A_{3}B\parallel A_{5}B$ and meeting AB at B’.

Step: IX- From B’ point draw and meeting AC at C’

Thus, is the required triangle, each of whose sides is ${\left(\frac{3}{5}\right)}^{\mathrm{th}}$ of the corresponding sides of.