Question

Draw a rough figure to illustrate the following statements:

(1) In ∆PQR, seg QN is an altitude.
(2) In ∆NPK, seg PS is a median.
(3) In ∆BCD, seg CM is a median and CE is an altitude.

Answer 1

(1) We have to draw seg QN as an altitude.
Therefore, it will be a perpendicular drawn from vertex Q to the opposite side PR of the triangle .


(2) We have to draw seg PS as a median.
Therefore, it will be the line segment joining vertex P of the triangle to the mid-point of its opposite side NK.


(3) We have to draw seg CM as a median and CE as an altitude.
Therefore, CE will be the perpendicular and CM will be the mid-point drawn from vertex C to the opposite side BD of the triangle.