Draw a triangle with sides 6cm, 8cm and 10cm. Using a common vertex and with the 10cm side, construct a similar triangle with the ratio of corresponding sides 2:1.

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Solution

1. Draw the given triangle with base 6cm and sides 8cm and 10 cm respectively.
2. From B, draw a ray BX. Cut 2 arcs of equal length on the ray BX at $B_{1}$ and $B 2$ .
3. Draw a line from $B_{1}$ to C.
4. From $B_{2}$ , draw another line parallel to $B_{3} C$ , cutting the extended line BC at $C_{1}$ .
5. From $C_{1}$ , draw another line parallel to AC, cutting the extended line BA at $A_{1}$ .
Triangle $A_{1} B C_{1}$ is the required similar triangle to ABC with the ratio of corresponding sides 2:1.

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