Draw a triangle ABC with the given specifications, AB = 6.5 cm, AC = 7 cm, and BC = 3 cm.
Draw perpendicular bisectors of sides AB and AC, they meet at O. Join OB.
So, O is the centre and OB is the radius of the circumcircle of
△ABC.
From the above constructions, we see that the circumradius of
△ABC is 3.5 cm.